x^2-0.8x+0.08=0

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Solution for x^2-0.8x+0.08=0 equation:



x^2-0.8x+0.08=0
a = 1; b = -0.8; c = +0.08;
Δ = b2-4ac
Δ = -0.82-4·1·0.08
Δ = 0.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{0.32}}{2*1}=\frac{0.8-\sqrt{0.32}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{0.32}}{2*1}=\frac{0.8+\sqrt{0.32}}{2} $

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